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Jayu_Patidar

New Member
Messages
12
Location
England
Hi I was just on the reptile calculator app and it gave me the results but when I tried to put my breeding pair into a punnet square I couldn't see how they got that. Could someone pls explain how the app created those results in a punnet square?
970bd263885612d513de39d28a1be40e.jpg



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Alceste

Member
Messages
30
Location
United States
You're starting with a Bell, so every baby will get a het for that gene. Imagine the calculator shows 1 result, every animal having het bell. Then you have Mack, mack is dominant so each egg has a 50% chance of being mack. So the calculator now splits the 1 result into 2, 50% mack het bell and 50% normal het bell. Lastly the het eclipse further divides your results. The het is only passed on to 50% of the babies, so the calculator again splits your results into what you see above. It's effectively showing you every combo you may end up with. But another way of looking at it is simply to say every individual egg will be het bell and stands a 50% chance of being mack snow and 50% chance of being het eclipse.
 
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Neon Aurora

Neon Aurora

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1,376
Location
New Mexico
UUr5Xfb.png


Here is how it works out on a punnett square. The alleles I chose are:

M - Wildtype (or rather, non-mack snow)
m - Mack Snow
b - Bell albino
e - Eclipse

The dominant forms of the recessives (E and B) are just the wildtype forms of eclipse and bell albino respectively. I feel like it's a little confusing having the M be wildtype, but what I was going for to make it easier is to ignore the actual wildtype allele. Instead, I have mack snow (m) and non-mack snow (M), so a homozygous MM would just be a non-mack snow (wildtype).

So the way the parents worked out: MMEEBB is a completely wildtype gecko. mM (one mack allele and one wiltype, so a mack snow but not a super snow which would have two mack snow alleles (mm)) eE (one allele for eclipse, so het eclipse) bb (two alleles for bell, so a visual bell albino)

Thank you for being interested in actually understanding the punnett squares! They are not hard and I think more people need to learn to do it manually (I cheated and used a program that just allowed me to enter the alleles and select dominance, but I've done MANY punnett squares manually in my life).

Let me know if you have any questions about the image.
 
Last edited:
J

Jayu_Patidar

New Member
Messages
12
Location
England
Neon Aurora said:
UUr5Xfb.png


Here is how it works out on a punnett square. The alleles I chose are:

M - Wildtype (or rather, non-mack snow)
m - Mack Snow
b - Bell albino
e - Eclipse

The dominant forms of the recessives (E and B) are just the wildtype forms of eclipse and bell albino respectively. I feel like it's a little confusing having the M be wildtype, but what I was going for to make it easier is to ignore the actual wildtype allele. Instead, I have mack snow (m) and non-mack snow (M), so a homozygous MM would just be a non-mack snow (wildtype).

So the way the parents worked out: MMEEBB is a completely wildtype gecko. mM (one mack allele and one wiltype, so a mack snow but not a super snow which would have two mack snow alleles (mm)) eE (one allele for eclipse, so het eclipse) bb (two alleles for bell, so a visual bell albino)

Thank you for being interested in actually understanding the punnett squares! They are not hard and I think more people need to learn to do it manually (I cheated and used a program that just allowed me to enter the alleles and select dominance, but I've done MANY punnett squares manually in my life).

Let me know if you have any questions about the image.
Click to expand...

Thanks so much for explaining how it actually works!!! It has elaborated my understanding of the punnet square so much. Really appreciated.
 
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