copy1/cop2 percentages..are these right?

[Laporte]

Hi all, I'm hopin someone can help me sort out the percentages for heterozygous offspring,

Here's how I'm seeing it, please tell me what's right what's wrong and where 66% comes from, I'm seeing it all over not sure where to place it, or how it's being used.


I'll use Bell albino as an example:

copy2 bell X copy2 bell = 100% copy2 bell

copy2 bell X copy1 bell = 50%normal, 50% copy2, and 50% of normals are copy1??

copy2 bell X normal = 100% normals, 50% of normals are copy1??

copy1 bell X copy1 bell = 50% copy2 and 50% are copy1

copy1 bell X normal = 100% normals, and 50% are copy1


I think that's all the combos,

*please no one use the above info until it gets sorted out*

Any help is greatly appreciated,
Thanks

 

[tiedxupxinxknots]

only 2 were right these were wrong


copy2 bell X copy1 bell = 50%normal, 50% copy2, and 50% of normals are copy1??

copy2 bell X normal = 100% normals, 50% of normals are copy1??

copy1 bell X copy1 bell = 50% copy2 and 50% are copy1

corrections:
copy2 bell X copy1 bell = 50% (2) copy 50% (1) copy (normals are one copy)
copy2 bell X normal = 100% (1) copy\
copy1 bell X copy1 bell = 25% (2) copy 50% (1) copy 25% normal

now 66% is used when het x het once the egg hatches and its not 2 copies then out of the 3 possible outcomes one is crossed out leaving it a chance of 2outcomes so it is 66% chance of being het i dont think i explained it right though lol

 

[Laporte]

only 2 were right these were wrong


copy2 bell X copy1 bell = 50%normal, 50% copy2, and 50% of normals are copy1??

copy2 bell X normal = 100% normals, 50% of normals are copy1??

copy1 bell X copy1 bell = 50% copy2 and 50% are copy1

corrections:
copy2 bell X copy1 bell = 50% (2) copy 50% (1) copy (normals are one copy)
copy2 bell X normal = 100% (1) copy\
copy1 bell X copy1 bell = 25% (2) copy 50% (1) copy 25% normal

now 66% is used when het x het once the egg hatches and its not 2 copies then out of the 4 possible outcomes one is crossed out leaving it a chance of 3 outcomes so it is 66% chance of being het i dont think i explained it right though lol

great thanks for the corrections, and if I understand your explanation correctly then:

there are three outcomes,
25%copy2
50% het(copy1)
and 25%normal no copy

take out the copy2

your left with 2parts copy2 and 1part normal no copy
hence 66%

is that it?

 

[tiedxupxinxknots]

great thanks for the corrections, and if I understand your explanation correctly then:

there are three outcomes,
25%copy2
50% het(copy1)
and 25%normal no copy

take out the copy2

your left with 2parts copy2 and 1part normal no copy
hence 66%

is that it?

you are left with (1) copy or no copy because you cross out the (2) copy.

 

[Laporte]

you are left with (1) copy or no copy because you cross out the (2) copy.

Alright I think I got it, thank you much for your help in clearing that up for me.

 

[LEO_80]

WOW! this stuff can be confusing.

 

[Laporte]

WOW! this stuff can be confusing.

No doubt, It's all in how you look at it, using punnett squares (if I knew how exactly) might be the better way of solving these problems, at least for 1 simple recessive gene anyway, once you start throwing lots of genes in there it gets really confusing haha