Genetics help

[swaltz]

I understand how to figure out genetics on a punnett square. But how would you set a square up for a single recessive X double recessive?

 

[Ipsl]

You have to have all traits represented in both parents.

So for example a Patternless x Bell Blizzard pairing would be pp AA AA x AA bb zz. Wich by the way equals al normal trip hets.

If you were to line them up so the traites were on the same allie it wouldnt work. What are you breeding? Ive mad a gecko calculator or you can just go here .

 

[swaltz]

I have a het Bell Albino / Tremper Albino (M) x Het Bell Albino (F).

 

[Nigel4less]

I definitely wouldnt cross the different albino strains its really frowned upon in the hobby.

 

[Ipsl]

So your saying a Temper het bell and a het bell? tt Ab x AA Ab?

 

[swaltz]

I definitely wouldnt cross the different albino strains its really frowned upon in the hobby.

They were crossed by accident. The female was sold to me as a Tremper when shes not, she is a bell. I have no Bell males so I was gonna breed back to try to get a male.

 

[Rep-Tails]

Ipsl sorry not to be mean but I think you missunderstood swaltz. He has a Dbl Het Tremper/Bell Albino. And a single Het Bell. Swaltz neither are actually albino? but one is carrying two albino strands and the other is carrying only one?

 

[Ipsl]

ohhhhh I did misunderstand thanks Rep

 

[Ipsl]

Here are the results from a double het Tremp and Bell with a het Bell:
0.127944946 At bb Bell het Tremper
0.249969482 At Ab Double het Bell Tremper
0.125976563 AA bb Bell
0.25 AA Ab het Bell
0.122085571 At AA het Tremper
0.124023438 AA AA Normal

 

[TokayKeeper]

the defining of your alleles is confusing the hell out of me....

Parentals =
male - Double het Tremper and Bell Albino
female - het Bell albino

The Male's traits would be like that of a dihybrid cross
T= normal
t= tremper albino
B= normal
b= Bell Albino

In order to set up the dihybrid cross for the female she'd have the following traits to add:
T= normal
B= normal
b= bell albino

The allelic combinations for the male would be: TB, Tb, tB, & tb

The allelic combinations for the female would be: TB, TB, Tb, & Tb

The resulting offspring would be as follows:

Het. Tremper Albino, Het. Bell Albino X Het. Bell Albino

12.5% WT (TTBB)
25% Het. Bell Albino, (TTBb)
12.5% Homozygous Bell Albino, (TTbb)
12.5% Het. Tremper Albino, (TtBB)
25% Het. Tremper Albino, Het. Bell Albino, (TtBb)
12.5% Het. Tremper Albino, Homozygous Bell Albino, (Ttbb)

Genetics Wizard.com

 

[TokayKeeper]

Here are the results from a double het Tremp and Bell with a het Bell:
0.127944946 At bb Bell het Tremper
0.249969482 At Ab Double het Bell Tremper
0.125976563 AA bb Bell
0.25 AA Ab het Bell
0.122085571 At AA het Tremper
0.124023438 AA AA Normal

WHY do you have 3 alleles (A, t, and b) in a dihybrid cross?

 

[Rep-Tails]

Tokay thats more along the lines of what I was thinking

 

[Ipsl]

I just use A for a non "blank gene" Like non albino or what ever. So a normal is AA AA. Just how I set it up.

 

[TokayKeeper]

I just use A for a non "blank gene" Like non albino or what ever. So a normal is AA AA. Just how I set it up.

yes, but you also have t and b in there, representing recessive genes for b, I assume bell, and t I assume tremper....but that's not how it works, unless you want to confuse people.

See my post before this thread went to 2 pages. That's the appropriate, genetics course way to setting up a dihybrid cross. There should not be 3 letters representing just 2 traits. A 3rd letter equates to a 3rd trait being factored in, which would be a trihybrid cross.

 

[Ipsl]

Simple enough to fix thanks for the input Tokay

 

[TokayKeeper]

I understand how to figure out genetics on a punnett square. But how would you set a square up for a single recessive X double recessive?

I have a het Bell Albino / Tremper Albino (M) x Het Bell Albino (F).

Now, let's see if I can make this easier for you....

Since you know the male is het bell albino and so is the female, you can do just a simple punnett square for that particular trait. That is unless you know you're het bell female to be carrying another trait.

If she isn't, then you'll have a 3:1 ratio from the het to het crossing; 3 normals and 1 albino. And, just to throw this out there for those that don't know or understand. Of those 3 normals 2 should be het bell albino and 1 will be a plain ole normal leo. 2/3 = 0.6666666666666666666666666666666666666666666666666667 (times 100 = 66.6667%), thus how one gets the 66% possible het figure. And technically since 66.6666666666666 rounds up to 7 it should be 67% if you want to do whole numbers