SHTCTB bred to a SHTCTB = ???

[leopardgeckos96]

ive had some people tell me SHTCTB bred to a SHTCTB = HT???
But shouldnt it be SHTCTB x SHTCTB = 100% SHTCTB???
Right?
And now for a sunglow question
Tremper albino x SHTCTB = 100% SHTCTB with 50% of them being het tremper albino

Then i breed the hopefully SHTCTB het tremper to the Tremper and get
50% tremper sunglow and 50% SHTCTB het tremper?
But if the gecko i breed to back to the tremper isnt het for tremper the first cycle just starts over so the babies will be 100% SHTCTB looking and 50% of them will be het for tremper?

Is this correct??
Thanks in advance,
Quinton

 

[cassadaga]

1. SHTCTB x SHTCTB = 100% SHTCTB???

You will probably get mostly SHTCTB but some may have more spotting, less tangerine or carrot tail color.

2. And now for a sunglow question
Tremper albino x SHTCTB = 100% SHTCTB with 50% of them being het tremper albino

You will get varying degrees of hypo tangs maybe with some carrot tail, and 100% of the babies will be het for Tremper.

3. Then i breed the hopefully SHTCTB het tremper to the Tremper and get
50% tremper sunglow and 50% SHTCTB het tremper?
But if the gecko i breed to back to the tremper isnt het for tremper the first cycle just starts over so the babies will be 100% SHTCTB looking and 50% of them will be het for tremper?

The results of this breeding will be similar to the first question, except half will be albino, and half wont. Since 100% of the babies will be het Tremper, you don't have to worry about the second part of this question, but I'd like to point out that if neither parents are at least het Tremper, no babies can possibly get the Tremper gene.

 

[Styles]

Is this the same pattern for all morphs? What would I get if I breed dreamsicle X dreamsicle?

 

[thegeckoguy23]

Is this the same pattern for all morphs? What would I get if I breed dreamsicle X dreamsicle?

When ever you breed the same morhs together you well get the super form if there is one and if there is not a super form you well get the same morph and usually there can be a chance of getting normals

 

[Taquiq]

Is this the same pattern for all morphs? What would I get if I breed dreamsicle X dreamsicle?

Dreamsickle x Dreamsickle=

6.25% Super Snow RAPTOR
6.25% Super Snow RAPTOR 2 copy Enigma
12.5% Super Snow RAPTOR 1 copy Enigma
12.5% Mack Snow RAPTOR
12.5% Dreamsickle that's 2 copy Enigma
25% Dreamsickle that's 1 copy Enigma
6.25% RAPTOR
6.25% NOVA (RAPTOR Enigma) 2 copy Enigma
12.5% NOVA 1 copy Enigma

 

[Styles]

My apologies OP and thank you Taquiq. What are the differences in the 1 copy and 2 copy? Sorry I am still trying to learn all the genetics and hets stuff.

 

[Taquiq]

If you breed a 1 copy Enigma to a Non Enigma, 50% of the babies will be Enigma and 50% will be Non Enigma. If you breed a 2 copy Enigma to a Non Enigma all of the babies will be Enigma. I don't think there are any differences in phenotype between the 2.

 

[Styles]

So a 1copy x 1copy = 2copy? Again thank- you Taquiq, I am reading through the vmsherp's website, just haven't had the time to sit down and read all the pages as of yet.

 

[Tommy13b]

When ever you breed the same morhs together you well get the super form if there is one and if there is not a super form you well get the same morph and usually there can be a chance of getting normals

This is only true in super snows bud, and you only get normals if you have hets.

 

[Taquiq]

So a 1copy x 1copy = 2copy? Again thank- you Taquiq, I am reading through the vmsherp's website, just haven't had the time to sit down and read all the pages as of yet.

1 copy x 1 copy=

25% 2copy
50% 1copy
25% no copies

Think of it this way. If you breed two 1 copy Enigmas together they would be Ae. The "A" representing 1 copy of normal and the "e" representing 1 copy of Enigma. So if you did punnet squares then it would look like this.

................... A......................................E


A................ AA (25% Normal) ............. AE (25% 1 copy Enigma)



E................AE (25% 1 copy Enigma)..... EE (25% 2 copy Enigma)

Since there are two 25% 1 copy Enigmas add them together to get 50%. So the total outcome would be...

25% Non Enigma
50% 1 copy Enigma
25% 2 copy Enigma

 

[Styles]

Ok, I see now. Thank you again. I am sure its not gonna be the last of my questions. Again sorry to the OP, I started out having the same thing in mind, so I didn't want to start a whole new thread but then I got a little side tracked.

 

[cassadaga]

There is so much misinformation in this thread I wouldn't know how to set it straight.

 

[Taquiq]

Me?

 

[Styles]

There is so much misinformation in this thread I wouldn't know how to set it straight.

Interested in knowing, I read through a lot of these threads and I don't want to be misinformed.

 

[cassadaga]

I must have posted this in the wrong thread, but now I can't remember what thread it was supposed to be in.

 

[fl_orchidslave]

:dizzy2::huh2: